@graphql-tools/executor@1.2.7
Patch Changes
-
#6280
7dcd0af
Thanks @ardatan! - Since the executor is version agnostic, it should
respect the schemas created with older versions.So if a type resolver returns a type instead of type name which is required since
graphql@16
,
the executor should handle it correctly.See the following example:
// Assume that the following code is executed with `graphql@15` import { execute } from '@graphql-tools/executor' const BarType = new GraphQLObjectType({ name: 'Bar', fields: { bar: { type: GraphQLString, resolve: () => 'bar' } } }) const BazType = new GraphQLObjectType({ name: 'Baz', fields: { baz: { type: GraphQLString, resolve: () => 'baz' } } }) const BarBazType = new GraphQLUnionType({ name: 'BarBaz', types: [BarType, BazType], // This is the resolver that returns the type instead of type name resolveType(obj) { if ('bar' in obj) { return BarType } if ('baz' in obj) { return BazType } } }) const QueryType = new GraphQLObjectType({ name: 'Query', fields: { barBaz: { type: BarBazType, resolve: () => ({ bar: 'bar' }) } } }) const schema = new GraphQLSchema({ query: QueryType }) const result = await execute({ schema, document: parse(/* GraphQL */ ` query { barBaz { ... on Bar { bar } ... on Baz { baz } } } `) }) expect(result).toEqual({ data: { barBaz: { bar: 'bar' } } })